Jacksonville linebacker Foye Oluokun has been named the AFC Defensive Player of the Week after a game-changing performance that fueled the Jaguars’ victory. He set the tone early and carried that intensity throughout the contest.

Oluokun posted a team-high 10 tackles, including several drive-stopping plays on third down. More importantly, he made the highlight of the game with a diving interception in the second half. That turnover shifted momentum firmly toward Jacksonville and gave the offense a short field. As a result, the Jaguars capitalized and built a lead they never surrendered.

Jaguars’ Foye Oluokun Wins AFC Defensive Player of the Week

The Defensive Anchor

Since arriving in 2022, Oluokun has consistently ranked near the top of the NFL in tackles. He diagnoses plays quickly, c

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